Problem to solve
Solve \[-10x+3y+z=-2\], \[3x-2y+5z=4\], \[-6x+4y+2z=1\]
Solution
STEP 1
Solve the following system:
{-10 x + 3 y + z = -2
3 x - 2 y + 5 z = 4
-6 x + 4 y + 2 z = 1
STEP 2
Express the system in matrix form:
(-10 | 3 | 1
3 | -2 | 5
-6 | 4 | 2)(x
y
z) = (-2
4
1)
STEP 3
Write the system in augmented matrix form and use Gaussian elimination:
(-10 | 3 | 1 | -2
3 | -2 | 5 | 4
-6 | 4 | 2 | 1)
STEP 4
Add 3/10 × (row 1) to row 2:
(-10 | 3 | 1 | -2
0 | -11/10 | 53/10 | 17/5
-6 | 4 | 2 | 1)
STEP 5
Multiply row 2 by 10:
(-10 | 3 | 1 | -2
0 | -11 | 53 | 34
-6 | 4 | 2 | 1)
STEP 6
Subtract 3/5 × (row 1) from row 3:
(-10 | 3 | 1 | -2
0 | -11 | 53 | 34
0 | 11/5 | 7/5 | 11/5)
STEP 7
Multiply row 3 by 5:
(-10 | 3 | 1 | -2
0 | -11 | 53 | 34
0 | 11 | 7 | 11)
STEP 8
Add row 2 to row 3:
(-10 | 3 | 1 | -2
0 | -11 | 53 | 34
0 | 0 | 60 | 45)
STEP 9
Divide row 3 by 15:
(-10 | 3 | 1 | -2
0 | -11 | 53 | 34
0 | 0 | 4 | 3)
STEP 10
Divide row 3 by 4:
(-10 | 3 | 1 | -2
0 | -11 | 53 | 34
0 | 0 | 1 | 3/4)
STEP 11
Subtract 53 × (row 3) from row 2:
(-10 | 3 | 1 | -2
0 | -11 | 0 | -23/4
0 | 0 | 1 | 3/4)
STEP 12
Divide row 2 by -11:
(-10 | 3 | 1 | -2
0 | 1 | 0 | 23/44
0 | 0 | 1 | 3/4)
STEP 13
Subtract 3 × (row 2) from row 1:
(-10 | 0 | 1 | -157/44
0 | 1 | 0 | 23/44
0 | 0 | 1 | 3/4)
STEP 14
Subtract row 3 from row 1:
(-10 | 0 | 0 | -95/22
0 | 1 | 0 | 23/44
0 | 0 | 1 | 3/4)
STEP 15
Divide row 1 by -10:
(1 | 0 | 0 | 19/44
0 | 1 | 0 | 23/44
0 | 0 | 1 | 3/4)
STEP 16
Collect results:
Answer: | 
 | {x = 19/44
y = 23/44
z = 3/4