Problem to solve
Solve \[\frac{2x-1}{4}+\frac{x-2y}{3}=4+x\], \[\frac{x+y}{3}-[x-y]=-2y+1\]
Solution
STEP 1
Solve the following system:
{1/4 (2 x - 1) + 1/3 (-2 y + x) = x + 4 | (equation 1)
-x + y + (y + x)/3 = -2 y + 1 | (equation 2)
STEP 2
Express the system in standard form:
{-x/6 - (2 y)/3 = 17/4 | (equation 1)
-(2 x)/3 + (10 y)/3 = 1 | (equation 2)
STEP 3
Swap equation 1 with equation 2:
{-(2 x)/3 + (10 y)/3 = 1 | (equation 1)
-x/6 - (2 y)/3 = 17/4 | (equation 2)
STEP 4
Subtract 1/4 × (equation 1) from equation 2:
{-(2 x)/3 + (10 y)/3 = 1 | (equation 1)
0 x - (3 y)/2 = 4 | (equation 2)
STEP 5
Multiply equation 1 by 3:
{-(2 x) + 10 y = 3 | (equation 1)
0 x - (3 y)/2 = 4 | (equation 2)
STEP 6
Multiply equation 2 by 2:
{-(2 x) + 10 y = 3 | (equation 1)
0 x - 3 y = 8 | (equation 2)
STEP 7
Divide equation 2 by -3:
{-(2 x) + 10 y = 3 | (equation 1)
0 x+y = -8/3 | (equation 2)
STEP 8
Subtract 10 × (equation 2) from equation 1:
{-(2 x)+0 y = 89/3 | (equation 1)
0 x+y = -8/3 | (equation 2)
STEP 9
Divide equation 1 by -2:
{x+0 y = -89/6 | (equation 1)
0 x+y = -8/3 | (equation 2)
STEP 10
Collect results:
Answer: | 
 | {x = -89/6
y = -8/3