Problem to solve
Solve \[\frac{x+2}{2}+\frac{3y-1}{4}=-1\], \[2x+y-2[3x-4y]=x+3\]
Solution
STEP 1
Solve the following system:
{(x + 2)/2 + 1/4 (3 y - 1) = -1 | (equation 1)
2 x - 2 (-4 y + 3 x) + y = x + 3 | (equation 2)
STEP 2
Express the system in standard form:
{x/2 + (3 y)/4 = -7/4 | (equation 1)
-(5 x) + 9 y = 3 | (equation 2)
STEP 3
Swap equation 1 with equation 2:
{-(5 x) + 9 y = 3 | (equation 1)
x/2 + (3 y)/4 = -7/4 | (equation 2)
STEP 4
Add 1/10 × (equation 1) to equation 2:
{-(5 x) + 9 y = 3 | (equation 1)
0 x+(33 y)/20 = -29/20 | (equation 2)
STEP 5
Multiply equation 2 by 20:
{-(5 x) + 9 y = 3 | (equation 1)
0 x+33 y = -29 | (equation 2)
STEP 6
Divide equation 2 by 33:
{-(5 x) + 9 y = 3 | (equation 1)
0 x+y = -29/33 | (equation 2)
STEP 7
Subtract 9 × (equation 2) from equation 1:
{-(5 x)+0 y = 120/11 | (equation 1)
0 x+y = -29/33 | (equation 2)
STEP 8
Divide equation 1 by -5:
{x+0 y = -24/11 | (equation 1)
0 x+y = -29/33 | (equation 2)
STEP 9
Collect results:
Answer: | 
 | {x = -24/11
y = -29/33