Problem to solve
Solve \[-4x+y-5z=2\], \[4x+2y+z=1\], \[2x-y+3z=4\]
Solution
STEP 1
Solve the following system: {-4 x + y - 5 z = 2 4 x + 2 y + z = 1 2 x - y + 3 z = 4
STEP 2
Hint: | Choose an equation and a variable to solve for. In the first equation, look to solve for y: {-4 x + y - 5 z = 2 4 x + 2 y + z = 1 2 x - y + 3 z = 4
STEP 3
Hint: | Solve for y. Add 5 z + 4 x to both sides: {y = 5 z + 4 x + 2 4 x + 2 y + z = 1 2 x - y + 3 z = 4
STEP 4
Hint: | Perform a substitution. Substitute y = 5 z + 4 x + 2 into the second and third equations: {y = 5 z + 4 x + 2 4 x + z + 2 (5 z + 4 x + 2) = 1 -2 z - 2 x - 2 = 4
STEP 5
Hint: | Expand the left hand side of the equation 4 x + z + 2 (5 z + 4 x + 2) = 1. 4 x + z + 2 (5 z + 4 x + 2) = 4 x + z + (10 z + 8 x + 4) = 11 z + 12 x + 4: {y = 5 z + 4 x + 2 (11 z + 12 x + 4) = 1 -2 z - 2 x - 2 = 4
STEP 6
Hint: | Choose an equation and a variable to solve for. In the second equation, look to solve for x: {y = 5 z + 4 x + 2 11 z + 12 x + 4 = 1 -2 z - 2 x - 2 = 4
STEP 7
Hint: | Isolate terms with x to the left hand side. Subtract 11 z + 4 from both sides: {y = 5 z + 4 x + 2 12 x = -11 z - 3 -2 z - 2 x - 2 = 4
STEP 8
Hint: | Solve for x. Divide both sides by 12: {y = 5 z + 4 x + 2 x = -(11 z)/12 - 1/4 -2 z - 2 x - 2 = 4
STEP 9
Hint: | Perform a substitution. Substitute x = -(11 z)/12 - 1/4 into the third equation: {y = 5 z + 4 x + 2 x = -(11 z)/12 - 1/4 -2 - 2 (-(11 z)/12 - 1/4) - 2 z = 4
STEP 10
Hint: | Expand the left hand side of the equation -2 - 2 (-(11 z)/12 - 1/4) - 2 z = 4. -2 - 2 (-(11 z)/12 - 1/4) - 2 z = ((11 z)/6 + 1/2) - 2 z - 2 = -z/6 - 3/2: {y = 5 z + 4 x + 2 x = -(11 z)/12 - 1/4 (-z/6 - 3/2) = 4
STEP 11
Hint: | Choose an equation and a variable to solve for. In the third equation, look to solve for z: {y = 5 z + 4 x + 2 x = -(11 z)/12 - 1/4 -z/6 - 3/2 = 4
STEP 12
Hint: | Isolate terms with z to the left hand side. Add 3/2 to both sides: {y = 5 z + 4 x + 2 x = -(11 z)/12 - 1/4 -z/6 = 11/2
STEP 13
Hint: | Solve for z. Multiply both sides by -6: {y = 5 z + 4 x + 2 x = -(11 z)/12 - 1/4 z = -33
STEP 14
Hint: | Perform a back substitution. Substitute z = -33 into the first and second equations: {y = 4 x - 163 x = 30 z = -33
STEP 15
Hint: | Perform a back substitution. Substitute x = 30 into the first equation: {y = -43 x = 30 z = -33
STEP 16
Hint: | Sort results. Collect results in alphabetical order: Answer: | | {x = 30 y = -43 z = -33
More problems
Number
001Solve \(3x+2y=5\), \(-4x+5y=2\)
002Solve \(-4x+5y+3=x+4\), \(6x-7y=2y-1\)
003Solve \(-5x+2y=-3+2x\), \(4x-2y+3=7-4x\)
004Solve \(3y+5x+1-2y=2y-3\), \(3y-2+5x=2x-3y+2\)
005Solve \(3x+5y=2\), \(-5x+6y=5\)
006Solve \(-\frac{2}{3}x+5y=4\), \(7x-5y=4\)
007Solve \( 4x-5y=3\), \(-2x+6y=-2\)
008Solve \(\frac{6}{5}x+\frac{3}{2}y=5\), \(-\frac{3}{5}x+y=5y+2\)
009Solve \(\frac{3}{2}x-\frac{1}{2}y=6x-2\), \(3x+\frac{2}{3}y=-2y-1\)
010Solve \(-2x+6y-4x=5x-3y+3\), \(7y+4x=9-2y\)
011Solve \(\frac{2x+y}{3}-\frac{2(x+y)}{4}=2\), \(-\frac{2(x-y)}{5}-\frac{x+2y}{2}=-1\)
012Solve \(-\frac{2(x-y)}{5}+\frac{2x-y}{2}=-1\), \(4(2x+3)-\frac{3x-4y}{2}=5\)
013Solve \(\frac{x+2}{2}+\frac{3y-1}{4}=-1\), \(2x+y-2(3x-4y)=x+3\)
014Solve \(\frac{2x-1}{4}+\frac{x-2y}{3}=4+x\), \(\frac{x+y}{3}-(x-y)=-2y+1\)
015Solve \(3(x-5y)+2(2x-1)=2(x-y)\), \(2(x-1)-3(x-y)=-3x\)
016Solve \(x-y+3z=2\), \(2x-3y=-4\), \(x+y+z=-2\)
017Solve \(-4x+y-5z=2\), \(4x+2y+z=1\), \(2x-y+3z=4\)
018Solve \(-10x+3y+z=-2\), \(3x-2y+5z=4\), \(-6x+4y+2z=1\)
019Solve \(4x-3y=7\), \(2x-3y+z=7\), \(4x-y+z=-8\)
020Solve \(-x+3y+2z=5\), \(-3x-2y+z=-4\), \(x-y+z=3\)
021Solve \(\frac{x}{3}-\frac{y}{2}+z=2\), \(-x-\frac{y}{3}+2z=3\), \(2x-3y+\frac{z}{3}=-1\)
022Solve \(2x-\frac{y}{3}+2z=-1\), \(x+y+\frac{z}{2}=-1\), \(x-2y+z=2\)
023Solve \(-\frac{3x}{2}+3y+z=2\), \(3x-y+z=5\), \(\frac{x}{3}-y+z=2\)
024Solve \(\frac{2x}{3}-2z=-2\), \(2y-4z=2\), \(\frac{x}{3}-5y=2\)
025Solve \(\frac{x}{2}-3z=-2\), \(3y-\frac{z}{2}=2\), \(x+3y-z=5\)
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Edited by tododemate® - 2021